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PG Diploma Solar Semester one Paper 3 Exam Section C
- April 21, 2026
- Posted by: iisemumbai
- Category: Question bank Uncategorized
Power, Voltage & Current
Q1. A solar panel operates at 36V and delivers 8A current. Calculate output power.
Answer:
P = V × I = 36 × 8 = 288 W
Q2. A PV module gives 48V and 12A. Find output power.
Answer:
P = 48 × 12 = 576 W
Q3. A DC load consumes 600W from a 24V battery bank. Calculate current drawn.
Answer:
I = P / V = 600 / 24 = 25 A
Q4. A 2kW inverter runs on 48V battery bank. Find battery current.
Answer:
I = 2000 / 48 = 41.67 A
Q5. A system draws 15A from 230V AC supply. Calculate load power.
Answer:
P = 230 × 15 = 3450 W or 3.45 kW
Energy Consumption
Q6. A 1.5kW load runs for 8 hours daily. Find daily energy use.
Answer:
Energy = 1.5 × 8 = 12 kWh/day
Q7. A 500W motor runs for 10 hours/day. Calculate daily consumption.
Answer:
0.5 × 10 = 5 kWh/day
Q8. A home uses 12 kWh/day. Find monthly usage for 30 days.
Answer:
12 × 30 = 360 kWh
Q9. A school consumes 75 kWh/day. Find annual consumption.
Answer:
75 × 365 = 27,375 kWh/year
Q10. A factory uses 4500 kWh/month. Find average daily use for 30 days.
Answer:
4500 / 30 = 150 kWh/day
Solar Array Sizing
Q11. Daily load is 6 kWh. Peak sun hours = 5. Find required PV size.
Answer:
6000 / 5 = 1200 W = 1.2 kW
Q12. Daily load is 10 kWh. Sun hours = 5.5. Find PV size.
Answer:
10000 / 5.5 = 1818 W ≈ 1.82 kW
Q13. Required system size is 5.4kW using 540W panels. Number of panels?
Answer:
5400 / 540 = 10 panels
Q14. A 7kW plant uses 350W modules. Find quantity required.
Answer:
7000 / 350 = 20 panels
Q15. A 3kW system uses 500W modules. Find modules needed.
Answer:
3000 / 500 = 6 modules
Battery Bank Design
Q16. Six batteries of 12V,150Ah in series. Find total voltage and Ah.
Answer:
Voltage = 12 × 6 = 72V
Capacity = 150Ah
Q17. Four batteries of 12V,200Ah in parallel. Find bank rating.
Answer:
Voltage = 12V
Capacity = 200 × 4 = 800Ah
Q18. Four 12V batteries in series-parallel (2S2P), each 100Ah. Find output.
Answer:
Voltage = 24V
Capacity = 200Ah
Q19. A 24V,300Ah battery bank stores how much energy?
Answer:
24 × 300 = 7200 Wh = 7.2 kWh
Q20. A 48V,200Ah battery bank stores total energy?
Answer:
48 × 200 = 9600 Wh = 9.6 kWh
Backup Time
Q21. A 24V,200Ah battery runs 1000W load. Find backup (ideal).
Answer:
Energy = 24×200 = 4800Wh
4800/1000 = 4.8 hours
Q22. A 48V,150Ah battery runs 1.5kW load. Backup time?
Answer:
48×150 = 7200Wh
7200/1500 = 4.8 hours
Q23. Battery energy = 9.6kWh, load = 2kW. Backup time?
Answer:
9.6 / 2 = 4.8 hours
Q24. Battery energy = 7.2kWh, load = 800W. Backup time?
Answer:
7200 / 800 = 9 hours
Q25. 12V,100Ah battery powers 120W DC load. Backup?
Answer:
1200Wh /120 = 10 hours
Solar Specifications
Q26. Module Voc = 49V. Max system voltage = 600V. Max modules in series?
Answer:
600 / 49 = 12.24
Use 12 modules
Q27. Module Vmp = 41V. Need 410V string voltage. Panels needed?
Answer:
410 / 41 = 10 panels
Q28. Panel Imp = 13A. Three strings in parallel. Total current?
Answer:
13 × 3 = 39A
Q29. Isc = 14A. Four strings parallel. Array Isc?
Answer:
14 × 4 = 56A
Q30. A 540W panel costs ₹16,200. Cost per watt?
Answer:
16200 / 540 = ₹30/W
Billing / Tariff
Q31. Monthly bill usage = 600 units. Tariff ₹8/unit. Bill amount?
Answer:
600 × 8 = ₹4,800
Q32. Commercial user consumes 1500 units at ₹10/unit. Cost?
Answer:
1500 × 10 = ₹15,000
Q33. A solar plant offsets 300 units/month at ₹9/unit. Savings?
Answer:
300 × 9 = ₹2,700/month
Q34. Annual saving ₹36,000. Monthly saving?
Answer:
36000 / 12 = ₹3,000/month
Q35. If monthly bill reduces from ₹8000 to ₹2500, savings?
Answer:
8000 – 2500 = ₹5,500/month
Efficiency / Generation
Q36. A 5kW plant generates 20 kWh/day. Specific generation?
Answer:
20 / 5 = 4 kWh/kW/day
Q37. A 3kW plant generates 12 units/day. Specific yield?
Answer:
12 / 3 = 4 units/kW/day
Q38. 10kW plant gives 45 units/day. Yield?
Answer:
45 / 10 = 4.5 units/kW/day
Q39. A 2kW system gives 300 kWh/month. Daily average?
Answer:
300 / 30 = 10 kWh/day
Q40. A 6kW system gives 900 units in 30 days. Daily output?
Answer:
900 / 30 = 30 units/day
Mixed Harder Numericals
Q41. Load = 8kWh/day. Sun hours = 4. Panel size?
Answer:
8000 / 4 = 2 kW
Q42. Need 48V system using 12V batteries. Batteries in series?
Answer:
48 / 12 = 4 batteries
Q43. Need 400Ah using 200Ah batteries at same voltage. Parallel units?
Answer:
400 / 200 = 2 batteries
Q44. Need 48V,400Ah using 12V,200Ah batteries. Quantity needed?
Answer:
4 in series × 2 parallel = 8 batteries
Q45. 5kW inverter at 90% efficiency delivers output power?
Answer:
5000 × 0.90 = 4500W useful output
Q46. Input required for 3kW output at 92% inverter efficiency?
Answer:
3000 / 0.92 = 3260.87W ≈ 3.26kW
Q47. A 540W panel gives only 85% due to losses. Actual output?
Answer:
540 × 0.85 = 459W
Q48. 20 panels of 540W each. Total DC capacity?
Answer:
20 × 540 = 10,800W = 10.8kW
Q49. 10.8kW plant generates 43.2 units/day. Yield per kW?
Answer:
43.2 / 10.8 = 4 units/kW/day
Q50. System cost ₹4,00,000. Annual saving ₹80,000. Payback period?
Answer:
400000 / 80000 = 5 years